How Do I Fix Sending XML Over An HTTP Servlet?

Over the past few weeks, some of our readers have reported that they have stumbled upon a servlet for sending xml over http.

ASR Pro: The #1 software for fixing Windows errors

  • 1. Download and install ASR Pro
  • 2. Open the program and click "Scan"
  • 3. Click "Repair" to start the restoration process
  • Solve your computer issues now with this reliable download.

    Below is the code I am working on to generate an XML file, not to mention having to recommend that XML file to the attached servlet every time I request an XML file. This is also local on my box. I was able to generate an XML file, but I’m not sure how to send this XML archive to one of my servlets so that I can parse this XML file in the doGet method.

      public fixed void args) main (String [] throws SAXException, XPathExpressionException, ParserConfigurationException, IOException,    TransformExceptionString Xml = generateXML ();send ("http: // localhost: 8080 / ServletExample / SampleServlet", xml);/ ** (Space) An easy way to generate your XML file * * /the fixed public string generateXML (String conn, String funcAddr) throws ParserConfigurationException, SAXException, IOException,    XPathExpressionException, TransformerExceptionDocumentBuilderFactory docFactory is DocumentBuilderFactory.newInstance ();DocumentBuilder docBuilder = docFactory.newDocumentBuilder ();// Some code to create an XML fileString xmlString = sw.toString ();// display xmlSystem.out.println ("This is definitely xml:  n" + xmlString);return xmlString;/ ** * Easy way to send XML to servlet class * * /public nullify static submit (String urladdress, String file) fires MalformedURLException, IOExceptionThe string character set  and - "UTF-8";String s = URLEncoder.encode (file, charset);// I don't know what to do here to get enough// above XML initiative I did for my husband and my servlet class. 

    send xml over http servlet

    my runs locally on your 8080. Below is a snippet directly from my servlet class –

      protected void doGet (HttpServletRequest, HttpServletResponse) throws ServletException, IOException    The bufferedreader implies request.getReader ();    // Parse the XML file here?    System.out.println (reader.readLine ()); 

    I created a servlet sort called SampleServlet on the dynamic project website being updated. I am currently running the server in debug mode. Below is the actual code of my servlet

      protected Avoid doGet (HttpServletRequest, HttpServletResponse) throws ServletException, IOException    Reader request BufferedReader = .getReader ();    System.out.println (reader.readLine ());protected void doPost (HttpServletRequest, HttpServletResponse response) throws ServletException, IOException   BufferedReader b = new BufferedReader (request.getReader ());     System.out.println (reader.readLine ()); 

    ASR Pro: The #1 software for fixing Windows errors

    Is your computer running slowly? Do you keep getting the Blue Screen of Death? Is your anti-virus software not doing its job properly? Well, have no fear, because ASR Pro is here! This powerful piece of software will quickly and easily repair all sorts of common Windows errors, protect your files from being lost or corrupted, and optimize your PC for maximum performance. You'll never have to worry about your computer crashing again - with ASR Pro on board, you're guaranteed a smooth, problem-free computing experience. So don't wait any longer - download ASR Pro today!

  • 1. Download and install ASR Pro
  • 2. Open the program and click "Scan"
  • 3. Click "Repair" to start the restoration process

  •      Sample Servlet        index.html      index.htm      index.jsp      default.html      default.htm      default.jsp               SampleServlet     example servlet       com.servlet.example.SampleServlet          example servlet      / SampleServlet    

    You need to set a breakpoint in the two strategies above. As soon as I click such a URL in the browser –

    Now I have created a new java project in Eclipse which is a great client and calls its servlet’s doPost method because I want to pass an XML file with my servlet as a request.

      public noise void main (String [] args)    HttpPost post = new HttpPost ("http: // localhost: 8080 / ServletExample / SampleServlet");    post.setHeader ("content type", "application / xml");   Message .setEntity (new StringEntity (generateNewXML ()));    HttpClient-Client = nnew DefaultHttpClient ();   The HttpResponse response includes client.Somehow execute (post); 

    , but as soon as I run my main program above for a Java application, it doesn’t hit the breakpoint I just placed in my servlet class. And I don’t know why this is planned and no exceptions are being made. Any idea why this is happening?

    1. Java
    2. Servlets
    3. Send file

    Send XML

    import java.io.BufferedInputStream; import java.io.IOException; import java.io.PrintWriter; import java.net.MalformedURLException; import java.net.URL; import java.net.URLConnection; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; public class ResourceServlet extends HttpServlet public void doGet (HttpServletRequest, HttpServletResponse response) , ServletException thrown, IOException thrown // Get the Web.xml ad from the servlet Line = file “/ WEB-INF / web.xml”; Urleu url is null; = URLConnection urlConn zero; = PrintWriter at zero; = BufferedInputStream buffer zero; = try out implies response.getWriter (); Url = getServletContext (). GetResource (file); // Set the response header response.setContentType ( “text / xml”); URLConn = URL. open connection (); // Connect to the URL rendered by web.xml urlConn.connect (); buf = new BufferedInputStream (urlConn.getInputStream ()); int readBytes = 0; while ((readBytes means buf.read ()) -1) ! = out.write (readBytes); Color = “# 7f0055″> catch throw new ServletException (mue.getMessage ()); catch (IOException ioe) throw new ServletException (ioe. getmessage ()); finally if (out! means zero) out.close (); if! = (buf null) buf.close (); public Color = “# 7f0055″> void , ServletException thrown, IOException thrown doGet (request, response);

    Similar Images In The Same Category

    send xml over http servlet

    Solve your computer issues now with this reliable download.